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Find the value of y and z

Find the value of y and z-example-1
User Charmian
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\qquad\qquad\huge\underline{{\sf Answer}} \huge♨

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~


\qquad \sf  \dashrightarrow \:3y = 90 \degree


\qquad \sf  \dashrightarrow \:y = 90 \degree / 3


\qquad \sf  \dashrightarrow \:y = 30 \degree

Now, Let's use Angle sum property of Triangle to solve for z :


\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree


\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree


\qquad \sf  \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)


\qquad \sf  \dashrightarrow \:4z = 180 \degree - (140\degree)


\qquad \sf  \dashrightarrow \:4z = 40 \degree


\qquad \sf  \dashrightarrow \:z = 40 \degree / 4


\qquad \sf  \dashrightarrow \:z = 10 \degree

I hope you understood the procedure, you can ask me in comments if you have any doubts.

User FeelRightz
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