1 Answer

FeelRightz · Answer 1 · 2023-01-26T04:30:24+0000

$\qquad\qquad\huge\underline{{\sf Answer}} \huge♨$

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

$\qquad \sf  \dashrightarrow \:3y = 90 \degree$

$\qquad \sf  \dashrightarrow \:y = 90 \degree / 3$

$\qquad \sf  \dashrightarrow \:y = 30 \degree$

Now, Let's use Angle sum property of Triangle to solve for z :

$\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree$

$\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree$

$\qquad \sf  \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)$

$\qquad \sf  \dashrightarrow \:4z = 180 \degree - (140\degree)$

$\qquad \sf  \dashrightarrow \:4z = 40 \degree$

$\qquad \sf  \dashrightarrow \:z = 40 \degree / 4$

$\qquad \sf  \dashrightarrow \:z = 10 \degree$

I hope you understood the procedure, you can ask me in comments if you have any doubts.

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