Answer:
a)
![E(T) = 0.2 E(Y) -1000= 0.2*20000 -1000=3000](https://img.qammunity.org/2021/formulas/mathematics/college/ah2lf5g72oos4nryafpdsd59aasqgmu0qf.png)
b)
c) Assuming 20 million of families and each one with a mean of income of 20000 for each family approximately then total income would be:
![E(T) = 20000000*20000= 40000 millions](https://img.qammunity.org/2021/formulas/mathematics/college/jiz8glj2ehwcc5npwdv1kkmsaam7ata9qt.png)
And if we replace into the formula of T we have:
![T = 0.2*400000x10^6 -1000= 790000 millions](https://img.qammunity.org/2021/formulas/mathematics/college/owoz8dcjiqcczpcmf1ri07b622ry6hib7u.png)
Approximately.
Explanation:
For this case we knwo that Y represenet the random variable "Income" and we have the following properties:
![E(Y) = 20000, Sd(Y) = 8000](https://img.qammunity.org/2021/formulas/mathematics/college/1p6738i5vmuijvkkqmy7bmgb3o4q7l646m.png)
We define a new random variable T "who represent the taxes"
![T = 0.2(Y-5000) = 0.2Y -1000](https://img.qammunity.org/2021/formulas/mathematics/college/xztu59um04jjvenw3i3ks8lnot4ekmeca4.png)
Part a
For this case we need to apply properties of expected value and we have this:
![E(T) = E(0.2 Y -1000)](https://img.qammunity.org/2021/formulas/mathematics/college/edd0kfwkj5bai64kwhqewt8opkvevfyi8b.png)
We can distribute the expected value like this:
![E(T) = E(0.2 Y) -E(1000)](https://img.qammunity.org/2021/formulas/mathematics/college/7shf2bm99u41pfmeyywhgldywch6yx1shw.png)
We can take the 0.2 as a factor since is a constant and the expected value of a constant is the same constant.
![E(T) = 0.2 E(Y) -1000= 0.2*20000 -1000=3000](https://img.qammunity.org/2021/formulas/mathematics/college/ah2lf5g72oos4nryafpdsd59aasqgmu0qf.png)
Part b
For this case we need to first find the variance of T we need to remember that if a is a constant and X a random variable
![Var(aX) = a^2 Var(X)](https://img.qammunity.org/2021/formulas/mathematics/college/61tuyj9fvfsfbvu7y0ld6zfxgzoj8jjdzp.png)
![Var(T) = Var (0.2Y -1000)](https://img.qammunity.org/2021/formulas/mathematics/college/awft6ffagi7owg5h1kzaerlksvrgnjw4ln.png)
![Var(T)= Var(0.2Y) -Var(1000) + 2 Cov(0.2Y, -1000)](https://img.qammunity.org/2021/formulas/mathematics/college/pzgxjdimtttoxkabmvptaxgv1thqeky57k.png)
The covariance between a random variable and a constant is 0 and a constant not have variance so then we have this:
![Var(T) =0.2^2 Var(Y)](https://img.qammunity.org/2021/formulas/mathematics/college/psj9fobnuufquvuf3i9a5jay5bmpmbhwbk.png)
And the deviation would be:
Part c
Assuming 20 million of families and each one with a mean of income of 20000 for each family approximately then total income would be:
![E(T) = 20000000*20000= 40000 millions](https://img.qammunity.org/2021/formulas/mathematics/college/jiz8glj2ehwcc5npwdv1kkmsaam7ata9qt.png)
And if we replace into the formula of T we have:
![T = 0.2*400000x10^6 -1000= 790000 millions](https://img.qammunity.org/2021/formulas/mathematics/college/owoz8dcjiqcczpcmf1ri07b622ry6hib7u.png)
Approximately.