Question

The area of a rectangle is 32a^3b^4 square units. The length is 4a^2b. Find the width. show your work

Answer 1

Step-by-step explanation: 32a^3 is -8 < a < - 8 axis interceptions 32a^3 vertical asymphotes None Extreme points of a32a^3 0,0

Answer 2

The answer to your question is width = 8ab³

Explanation:

Data

Area = 32a³b⁴ u²

length = 4a²b u

Formula

Area of a rectangle = width x length

Solve for width

width =
`(Area)/(length)`

Substitution

width =
`(32a^(3)b^(4))/(4a^(2)b)`

Simplify using rules of exponents, just remember that in a division we subtract the exponents and divide the coefficients normally.

width = 8 a²b³