Question

If your front lawn is 18.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snowflake has a mass of 2.10 mg.

Answer 1

47628 kg/hr

Step-by-step explanation:

Total area = 18*20 =360 ft^(2)

no .of snowflakes per minute = 1050*360 =378000

mass of snowflakes per minute = 378000*2.1*10^(-3) =793.8 kg/min

mass accumulated per hour = 793.8kg/min * 60min/hr =47628 kg/hr