110k views
0 votes
You are provided with a fuel cell that is designed to operate at j = 3 A∕cm2 and P = 1.5 W∕cm2. How much fuel cell active area (in cm2) is required to deliver 2 kW of electrical power? (This is approximately enough to provide power to the average American home.)

(a) 296.3 cm2
(b) 1333.3 cm2
(c) 444.4cm2
(d) 666.6 cm2

User Govert
by
5.1k points

1 Answer

4 votes

Answer:

correct option is b) 1333.3 cm²

Step-by-step explanation:

given data

power P = 1.5 W∕cm²

j = 3 A∕cm²

electrical power = 2 kW

solution

as given 1.5 W∕cm² power mean 1.5 W power operated by 1 cm²

so here 2 kW i.e here 2000 W power is operated in

2000 W power is operated =
(2000W*1cm^2)/(1.5W)

= 1333.33 cm²

so correct option is b) 1333.3 cm²

User Peter Bennink
by
5.7k points