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One AA battery in a flashlight stores 9400 J. The three LED flashlight bulbs consume 0.5 W. How many hours will the flashlight last?

User Ddprrt
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1 Answer

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Answer:

time = 5.22 hr

Step-by-step explanation:

Given data:

Energy of battery = 9400 J

Power consumed by three led bulb is 0.5 watt

we know Power is give as


Power = ( energy)/(time)

plugging all value and solve for time


time = (energy)/(power)


time = (9400)/(0.5)

time = 18,800 sec

in hour

1 hour = 3600 sec

therefore in 18,800 sec


time = (18800)/(3600) = 5.22 hr

User Dmitriy Apollonin
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