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Two rockets are lauched at the same time, but from different heights. The height y in feet of one rocket after t seconds is given by y = -16t² + 150t + 5. The height of the other rocket is given by y = -16t² + 160t. After how many second are the rockets at the same height?

1 Answer

2 votes

Answer:

0.5 seconds

Explanation:

Two rockets are launched at the same time, but from different heights.


y = -16t^2+ 150t + 5


y = -16t^2 + 160t

when the heights are same then y are equal. So equation both equations and solve for t


-16t^2+ 150t + 5= -16t^2+ 160t

Add -16t^2 on both sides


+ 150t + 5=160t

Subtract 150 t from both sides


5=10t

Divide 10 on both sides

t=0.5 seconds

User Michael Vieth
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