Question

Two rockets are lauched at the same time, but from different heights. The height y in feet of one rocket after t seconds is given by y = -16t² + 150t + 5. The height of the other rocket is given by y = -16t² + 160t. After how many second are the rockets at the same height?

Answer 1

0.5 seconds

Explanation:

Two rockets are launched at the same time, but from different heights.

`y = -16t^2+ 150t + 5`

`y = -16t^2 + 160t`

when the heights are same then y are equal. So equation both equations and solve for t

`-16t^2+ 150t + 5= -16t^2+ 160t`

Add -16t^2 on both sides

`+ 150t + 5=160t`

Subtract 150 t from both sides

`5=10t`

Divide 10 on both sides

t=0.5 seconds