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Upon reaching a velocity of 100fps, the pilot of the airplane decides to abort the take off and applies brakes and stops the airplane in 1000ft. What is the airplane’s deceleration?

User Deadbug
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1 Answer

4 votes

Answer:

5 ft/s²

Step-by-step explanation:

u = Initial velocity = 100 ft/s

v = Final velocity = 0

s = Displacement = 1000 ft

a = Acceleration

From equation of motion


v^2-u^2=2as\\\Rightarrow a=(v^2-u^2)/(2s)\\\Rightarrow a=(0^2-100^2)/(2* 1000)\\\Rightarrow a=-5\ ft/s^2


1\ ft/s^2=0.3048\ m/s^2\\\Rightarrow 5\ ft/s^2=5* 0.3048\ m/s^2=1.524\ m/s^2

The airplane's deceleration is 5 ft/s² or 1.524 m/s²

User Lll
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