Solve the system of linear equations 4x-2y=8 y=3/2x-2

Question

asked Jan 23, 2021 83.4k views

2 Answers

PSK · Answer 1 · 2021-01-28T15:55:21+0000

The solution to given system of linear equations is x = 4 and y = 4

Solution:

Given is a system of linear equation

$4x - 2y = 8 ---------- eqn 1\\\\y = (3)/(2)x - 2 ---------- eqn 2$

We have to solve the system of linear equations. We can solve the system by substitution method

Substitute eqn 2 in eqn 1

4x - 2((3)/(2)x - 2) = 8

Simplify the above equation

$4x - 2((3x-4)/(2)) = 8\\\\4x - (3x-4) = 8\\\\\text{Remove the parenthesis and solve }\\\\4x - 3x + 4 = 8\\\\x = 8 - 4\\\\x = 4$

Substitute x = 4 in eqn 2 to get value of y

$y = (3)/(2) * 4 -2\\\\y = 6 - 2\\\\y = 4$

Thus solution is x = 4 and y = 4