Question

Write the following quadratic in standard form. Then identify a, b, and c.
y² - 7y + 6 = -6

Answer 1

Therefore,

`y^(2)-7y+12=0` ....Standard form.

`a=1\\b=-7\\c=12` ......Numerical Coefficients.

Explanation:

Given:

`y^(2)-7y+6=-6`

To Find:

a ,b , c

Solution:

Quadratic:

A quadratic equation is an equation of the second degree.

Meaning it contains at least one term that is squared.

The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Here it is given as

`y^(2)-7y+6=-6`

Adding 6 on both the side we get

`y^(2)-7y+6+6=-6+6`

`y^(2)-7y+12=0`

Which is Quadratic Equation in STANDARD form Where,

`a=1\\b=-7\\c=12`

Therefore,

`y^(2)-7y+12=0` ....Standard form.

`a=1\\b=-7\\c=12` ......Numerical Coefficients.