Write the following quadratic in standard form. Then identify a, b, and c. y² - 7y + 6 = -6

Question

asked Sep 18, 2021 55.7k views

1 Answer

Kroegerama · Answer 1 · 2021-09-25T10:31:57+0000

Answer:

Therefore,

....Standard form.

$a=1\\b=-7\\c=12$ ......Numerical Coefficients.

Explanation:

Given:

y^(2)-7y+6=-6

To Find:

a ,b , c

Solution:

Quadratic:

A quadratic equation is an equation of the second degree.

Meaning it contains at least one term that is squared.

The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

Here it is given as

y^(2)-7y+6=-6

Adding 6 on both the side we get

y^(2)-7y+6+6=-6+6

y^(2)-7y+12=0

Which is Quadratic Equation in STANDARD form Where,

$a=1\\b=-7\\c=12$

Therefore,

....Standard form.

$a=1\\b=-7\\c=12$ ......Numerical Coefficients.