Register

A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 si…

A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 si…
5.6k views
1 vote
A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 significant digits?

User Namal
by
7.5k points

1 Answer

3 votes

Answer: the mole fraction for chloroform = 0.496

Explanation:Please see attachment for explanation

A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide-example-1
User Yaniv Golan
by
8.8k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Link Copied!