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A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 significant digits?
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A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 significant digits?

User Namal
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Answer: the mole fraction for chloroform = 0.496

Explanation:Please see attachment for explanation

A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide-example-1
User Yaniv Golan
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