Answer:
a) The length of the hypotenuse = 16 units.
Explanation:
Here, let us assume the given right angle triangle is Δ ABC.
Here. AC is the hypotenuse, which is divided in the ratio 1: 2 by the altitude BM.
⇒ AM : MC = 1: 2
Let us assume the common ratio = x
⇒ AM = x and MC = 2 x
Also. AM = 8 units
Solving this by common ratio of sides, we get:
![\implies (2x)/(x) = (x)/(8) \\\implies 2x^2 = 64\\\implies x^2 = 32\\\implies x = 4\sqrt 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/ilfk6t3moyue1xqzulu0unls7f6sdph1rn.png)
Hence, AM = 4√2 , MC = 2 (4√2)
⇒ AC = 12√2 units ≈ 16 units
Hence, the length of the hypotenuse = 16 units.