Question

A car accelerates uniformly from rest to a speed of 7.6 m/s in 4.6 s. How far does the car travel in that time?

Answer 1

The car will travel a distance of 17.45 meters.

Step-by-step explanation:

Given:

Initial velocity
`(V_i)` = 0

Final velocity
`(V_f)` = 7.6 m/s

Time taken = 4.6 s

Acceleration = (Final velocity - Initial Velocity )/time

`a=((V_f-Vi))/(t)= (7.6-0)/(4.6)=1.65\ ms^-2`

We have to calculate total distance traveled by the car.

Let the distance traveled be 'd'

Equation of motion:

`d=V_i(t)+(at^2)/(2)`

Plugging the values.

⇒
`d=V_i(t)+(at^2)/(2)`

⇒
`d=0+(1.65*(4.6)^2)/(2)`

⇒
`d=17.45\ m`

The car will travel a distance of 17.45 meters for the above case.