Question

(2,-1);y=-3/2x+6 how do you solve this equation?

Answer 1

`y = - (3)/(2)x + 2`

Explanation:

Assuming the question wants you to write and equation passing through (2,-1); and parallel to y=-3/2x+6.

Then we use the slope intercept form:

`y-y_1=m(x-x_1)`

We substitute the point and slope to get:

`y - - 1 = - (3)/(2) (x - 2)`

`y + 1 = - (3)/(2)x - + 3`

`y = - (3)/(2)x + 3 - 1`

`y = - (3)/(2)x + 2`

Note that parallel lines have the same gradient.