Answer
given,
initial velocity of the bullet = 1000 ft/s
angle made with horizontal = 75°
the horizontal and vertical component of the velocity = ?
Horizontal component of the velocity
![v_h = v cos \theta](https://img.qammunity.org/2021/formulas/physics/college/c8v86b8bsz1fja9ga9s4eg1ja5mlwobbyx.png)
![v_h = 1000 cos 75^0](https://img.qammunity.org/2021/formulas/physics/college/h7l4c44tawdswsuzdxih75gdtle0hxj2eu.png)
![v_h =258.82\ m/s](https://img.qammunity.org/2021/formulas/physics/college/4kjbe1hbvyw62ntz24xcxrsecvtjv3xdkf.png)
vertical component of the velocity
![v_v = v sin \theta](https://img.qammunity.org/2021/formulas/physics/college/6c9fxd90obddncyj60rjpavb4ar0a5jw0d.png)
![v_v = 1000 sin 75^0](https://img.qammunity.org/2021/formulas/physics/college/i86cw0sde386xidqb8560b5txmhkapbjpr.png)
![v_v =965.93\ m/s](https://img.qammunity.org/2021/formulas/physics/college/38ijvvjcooc0pmhktgyrt231ecr5htmr1k.png)
The horizontal and vertical component of the bullet is equal to
and
respectively.