Question

2) A particle of mass 19 g moves in a circle of radius

0.44 m. The kinetic energy of the particle is 3.7 J. What
is the magnitude of the net force on the particle?

Answer 1

Step-by-step explanation:

KE = ½ m v²

F = m v² / r

Therefore:

F = 2 KE / r

F = 2 (3.7 J) / (0.44 m)

F ≈ 17 N