Question

Calculate the mass of lead(ll)tetraoxosuplhatevi formed when 0.5mol-¹ of tetraoxosulphate vi when react with lead(ll)chloride​

Answer 1

The mass of lead(ll)tetraoxosuplhate formed when 0.5mol-¹ of tetraoxosulphate react with lead(ll)chloride​ is :

151.63 grams

Step-by-step explanation:

PbCl2 = lead(ll)chloride​

PbSO4 = lead(ll)tetraoxosuplhate

H2SO4 = hydrogen tetraoxosulphate

HCl = Hydrochloric acid

The balanced equation for the reaction is :

`PbCl_(2)+H_(2)SO_(4)\rightarrow PbSO_(4)+2HCl`

The stoichiometric coefficients indicates that :

1 mole PbCl2 = 1 mole H2SO4 = 1 mole PbSO4 = 2 mole HCl

1 mole H2SO4 produces = 1 mole PbSO4

0.5 mole produce = 0.5 mole of PbSO4

We have 0.5 mole of PbSO4

So , we are asked to calculate the mass of 0.5 mole pf PbSO4

Molar mass of PbSO4 = mass of Pb + Mass of S + 4(mass of O)

= 207.2 + 32.06 +4(16)

=303.26 grams

`mass = Molar\ mass* Moles`

`mass = 303.26* 0.5`

151.63 grams