Question

PLEASE HELPP!!

8,000,000 kg of water are at the verge of dropping over Niagara Falls to the rocks 50.0 m below. What is the change in gravitational potential energy as the water splashes on the rocks below? ( Calculate GPE final and GPE initial and then find the difference)

I will very much appreciate it thank you!

Answer 1

The Change in the Gravitational Potential Energy as the water splashes out on the rocks below is 3.92 * 10^9 J.

Step-by-step explanation:

If an object possess energy because of its position in a gravitational field is called as Gravitational Potential Energy.The formula for the Gravitational Potential Energy is given by,

GPE = mgh

where m represents the mass in kilograms,

g represents acceleration due to gravity (9.8 m/s^2 in Earth)

h is the height in meters.

mass = 8,000,000 kg, g = 9.8 m/s^2, initial height = 0

Initial GPE = 0

Final height = 50.0 m.

Final GPE = 8,000,000 * 9.8 * 50.0 = 3.92 * 10^9 J.

Change in Gravitational Potential Energy = Final GPE - Initial GPE

= (3.92 * 10^9) - 0

= 3.92 *10^9 J.