Answer:
0.2709
Explanation:
Since the sample size is large enough (np > 10 and nq > 10), we can estimate this with a normal distribution.
μ = p
μ = 0.68
σ = √(pq / n)
σ = √(0.68 (1 − 0.68) / 200)
σ = 0.033
x = 140 / 200
x = 0.7
Find the z score:
z = (x − μ) / σ
z = (0.7 − 0.68) / 0.033
z = 0.61
Use a calculator or table to find the probability.
P(Z > 0.61)
1 − P(Z < 0.61)
1 − 0.7291
0.2709