Length of diagonal of square is less than diameter of circle . Hence, the square will perfectly fit inside the circle without touching the edge of circle.
Step-by-step explanation:
Given:
Side length of square = S = 5 cm
Diameter of circle = D = 9 cm
To prove that the square with side length 5 cm will fit inside a circle with diameter 9 cm, without touching the edge of the circle.
A square has side length equal (similar length in all four sides). Diagonal of the square is greater than its side length and is the maximum dimension in case of a square.
So, if diagonal of square is less than diameter of circle; the square will fit inside the circle without touching its edges.
Let length of diagonal of square = L.
Using Pythagoras theorem to find L, .......................... (Refer attached figure)
Since L=7.07 cm,
Length of diagonal of square is less than diameter of circle.
The square will perfectly fit inside the circle without touching its edges.