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Not going to lie my brain is dead

Not going to lie my brain is dead-example-1
User Snouto
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2 Answers

5 votes

Answer:

5² + 5² = x²

x = 7.1

x < 9

Step-by-step explanation:

Use pythagoras theorem on the square by doing 5^2 + 5^2 = x^2 an you get x^2 = 50. x = square root 50 which is 7.1. As x is less than the diameter of the circle it will fit in the circle without touching the edges

User Qerts
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3.7k points
5 votes

Length of diagonal of square is less than diameter of circle . Hence, the square will perfectly fit inside the circle without touching the edge of circle.

Step-by-step explanation:

Given:

Side length of square = S = 5 cm

Diameter of circle = D = 9 cm

To prove that the square with side length 5 cm will fit inside a circle with diameter 9 cm, without touching the edge of the circle.

A square has side length equal (similar length in all four sides). Diagonal of the square is greater than its side length and is the maximum dimension in case of a square.

So, if diagonal of square is less than diameter of circle; the square will fit inside the circle without touching its edges.

Let length of diagonal of square = L.

Using Pythagoras theorem to find L, .......................... (Refer attached figure)


L^2 = S^2+S^2 = (5)^2 + (5)^2 = 25+25 = 50\\L=√(L^2) =√(50) = 7.07\ cm

Since L=7.07 cm,
7.07<9\ (L<D); Length of diagonal of square is less than diameter of circle.

The square will perfectly fit inside the circle without touching its edges.

Not going to lie my brain is dead-example-1
User Kirankumar Dafda
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3.4k points