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Coordinates, gradient and tangent work (see image).

Are my answers correct? -
a. P= (1.9,1.9) or (2,2) Q=(2,3)
b. (rise over run) 3-1.9/2-1.9 = 11
... and can anyone solve q.c -
c.

Coordinates, gradient and tangent work (see image). Are my answers correct? - a. P-example-1
User Marieliz
by
8.2k points

1 Answer

2 votes

Answer:

a)
P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)

b)
4x+2h

c)
4x

Explanation:

Given the curve


y=2x^2-5

a) If the x-coordinate of P is
x, then the y-coordinate is
2x^2-5, so point P has coordinates
(x,2x^2-5)

If the x-coordinate of Q is
x+h, then the y-coordinate is
2(x+h)^2-5 so point Q has coordinates
(x+h,2(x+h)^2-5)

b) The gradient of the secant RQ is


(y_Q-y_P)/(x_Q-x_P)\\ \\=((2(x+h)^2-5)-(2x^2-5))/((x+h)-x)\\ \\=(2(x+h)^2-5-x^2+5)/(x+h-x)\\ \\=(2(x+h)^2-2x^2)/(h)\\ \\=(2x^2+4xh+2h^2-2x^2)/(h)\\ \\=(4xh+2h^2)/(h)\\ \\=4x+2h

c) If
h\rightarrow 0, then the gradient
4x+2h\rightarrow 4x

User Charitoo
by
8.4k points

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