Find the critical value z Subscript alpha divided by 2 that corresponds to the given confidence level. 93%

Question

asked Mar 24, 2021 184k views

1 Answer

Flash Thunder · Answer 1 · 2021-03-29T01:33:48+0000

Answer:

$z_{{(\alpha)/(2)}}=z_(0.035)=1.81$

Explanation:

We are asked to compute
$z_{{(\alpha)/(2)}$ that corresponds to confidence level of 93%.

$93\%=(93)/(100)=0.93$

$\alpha=1-0.93=0.07$

$(\alpha)/(2)=(0.07)/(2)$

$(\alpha)/(2)=0.035$

Now, we will use normal distribution table to find the z-score that corresponds to area of 0.035.

z_(0.035)=-1.81

Therefore, the value of
$z_{{(\alpha)/(2)}$ is
.