Question

Find the critical value z Subscript alpha divided by 2 that corresponds to the given confidence level. 93​%

Answer 1

`z_{{(\alpha)/(2)}}=z_(0.035)=1.81`

Explanation:

We are asked to compute
`z_{{(\alpha)/(2)}` that corresponds to confidence level of 93%.

`93\%=(93)/(100)=0.93`

`\alpha=1-0.93=0.07`

`(\alpha)/(2)=(0.07)/(2)`

`(\alpha)/(2)=0.035`

Now, we will use normal distribution table to find the z-score that corresponds to area of 0.035.

`z_(0.035)=-1.81`

Therefore, the value of
`z_{{(\alpha)/(2)}` is
`1.81`.