Question

A 80kg cart goes around the inside of a vertical loop of a roller coaste. The radius of the loop is 5m and the cart moves at a speed of 8 m/s. What is the force exerted on the track on the cart?

Answer 1

1024 N

Step-by-step explanation:

mass, m= 80 kg

radius, r = 5 m

velocity, v = 8 m/s

The force on the track is

F = mv²/r

F = 80 x 8 x 8 / 5

F = 1024 N

Answer 2

F = 1024 N

Step-by-step explanation:

Given that,

Mass of the cart, m = 80 kg

Radius of the loop, r = 5 m

Speed of the cart, v = 8 m/s

To find,

the force exerted on the track on the cart.

Solution,

The force exerted on the track on the cart is called centripetal force. When an object moves in a circular path it possess centripetal force. It is given by :

`F=(mv^2)/(r)`

`F=(80* (8)^2)/(5)`

F = 1024 N

So, the force exerted on the track on the cart is 1024 N.