Question

An investor owns shares of Stock A and Stock B. The investor owns a total of 200 shares with a total value of $4000. How many shares of each stock does the investor own?Stock price

A. $9.50
B. $27.00
The investor owns___shares of Stock A. The investor owns___shares of Stock B.

Answer 1

No. of share of Stock A = 80 shares

No. of share of Stock B = 120 shares

Step-by-step explanation:

Let

No. of share of Stock A = X

No. of share of Stock B = Y

According to given condition

X + Y = 200 (Eq. 1)

9.50X + 27.0Y = 4000 (Eq. 2)

Multiplying (Eq. 1) by 27

27X + 27Y = 5400 (Eq. 3)

by Substracting (Eq. 2) from (Eq. 3)

(27X + 27Y) - (9.50X + 27.0Y) = 5400 - 4000

27X + 27Y - 9.50X - 27Y = 1400

27X - 9.50X = 1400

17.50X = 1400

X = 1400/17.50

X = 80

Y = 200 - 80 = 120

No. of share of Stock A = X = 80

No. of share of Stock B = Y = 120

Answer 2

80 shares and 120 shares

Step-by-step explanation:

Let us assume the number of shares owns of stock A be X and for Y it would be 200 - X

So, the equation would be

$9.50 × X + (200 - X) × $27 = $4,000

$9.50X + $5,400 - $27X = $4,000

-$17.5X = - $1,400

So X would be

= $1,400 ÷ $17.5

= 80

So Stock A shares be 80

And Stock B shares would be

= 200 shares - 80 shares

= 120 shares