Question

A 505-N rightward force is use to drag a large box across the floor with a constant velocity of 0.62 m/s. The coefficient of friction between the box and the floor is 0.7. Determine the mass of the box.

Answer 1

73.62 kg

Step-by-step explanation:

`F_(NET) = F_(a) + F_(f)`

`F_(NET) = 0`

Given;

`F_(a) = 505N`

`0= 505N + F_(f)`

`F_(f) = -505 N`

Also

`F_(f) = -\mu*m*g`

where m is the mass of the box,

g is acceleration due to gravity = 9.8 m/s²

`\mu` is coefficient of friction = 0.7

-505 = - (m*0.7*9.8)

-505 = -6.86 m

m = 505/6.86

m = 73.62 kg