Question

A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the horizontal. The block is displaced 57.6 m, and the coefficient of kinetic friction is 0.135. The acceleration of gravity is 9.8 m/s 2.

Answer 1

Step-by-step explanation:

Considering Work done by friction is asked

Given

mass of block
`m=15.4\ kg`

force
`F=182\ N`

inclination
`\theta =24^(\circ)`

block is displaced by
`s=57.6\ m`

coefficient of kinetic friction
`\mu _k=0.135`

Friction force
`F_r=\mu _kN`

Normal reaction
`N=mg-F\sin \theta =15.4* 9.8-182\sin (24)`

`N=76.9\ N`

Friction Force
`F_r=0.135* 76.9=10.38\ N`

Work done by friction force

`W=f_r\cdot s`

`W=10.38* 57.6=597.92\ N`