Answer:
The gravitational field strength on the surface of Mars = 3.72 m/s²
Step-by-step explanation:
Gravitational Field Strength: This can be defined as the force per unit mass which is exerted at that point. its direction is the force exerted on a mass in a gravitational field. The S.I unit of gravitational field strength is m/s²
Mathematically, Gravitational field is represented as,
g = F/m ..................... Equation 1.
m = F/g ..................... Equation 2.
Where g = gravitational Field Strength, F = force on the mass, m = mass of the body.
From the question,
Note: That The mass of the object is constant both on the surface of the earth and on the surface of Mars.
On the Surface of the earth,
Given: F = 785 N, g = 9.8 m/s²
Substituting this values into equation 2,
m = 785/9.8
m = 80.10 kg.
On the surface of Mars.
Given: m = 80.10 kg, F = 298.
Substituting into equation 2
g = 298/80.1
g = 3.72 m/s²
Thus the gravitational field strength on the surface of Mars = 3.72 m/s²