Answer:
option D
Step-by-step explanation:
given,
mass of the crate = 400 Kg
acceleration of the crate = 1 m/s²
frictional force = half its weight
weight of the crate,= mg
= 400 x 10 = 4000 N
frictional force,f = 0.5 x 4000 = 2000 N
using newtons second law
F - f = m a
F = m a + f
F = 400 x 1 + 2000
F = 2400 N
Horizontal force applied is equal to 2400 N
The correct answer is option D