Answer:
Kinetic energy, E = 662.27 J
Step-by-step explanation:
Given that,
Mass of the rock, m = 5.2 kg
It is falls off of a 13 meters cliff.
Force due to air resistance, F = 16 N
To find,
The kinetic energy when the rock hits the ground.
Solution,
Initial velocity of the rock will be zero as it is at rest. Let v is the final speed of the ball. It is given by :
![v=√(2gh)](https://img.qammunity.org/2021/formulas/physics/college/gxilsz3zlf320pmeovi24xonp5h2lv20v6.png)
![v=√(2* 9.8* 13)](https://img.qammunity.org/2021/formulas/physics/high-school/bv0dv03kpljaalxavagr6t4g7etj907qbi.png)
v = 15.96 m/s
The kinetic energy of the rock is given by :
![E=(1)/(2)mv^2](https://img.qammunity.org/2021/formulas/physics/high-school/2gzs2c11aqkuofmc8qdr1qjqc9xb6774bn.png)
![E=(1)/(2)* 5.2* (15.96)^2](https://img.qammunity.org/2021/formulas/physics/high-school/mb1ugundmdba8shrfi2i9irkfag7ejsz3s.png)
E = 662.27 J
So, the kinetic energy when the rock hits the ground is 662.27 J.