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A 5.2 kg rock falls off of a 13 m cliff. If air resistance exerts a force of 16 N, what is the kinetic energy when the rock hits the ground?

User Alveona
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1 Answer

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Answer:

Kinetic energy, E = 662.27 J

Step-by-step explanation:

Given that,

Mass of the rock, m = 5.2 kg

It is falls off of a 13 meters cliff.

Force due to air resistance, F = 16 N

To find,

The kinetic energy when the rock hits the ground.

Solution,

Initial velocity of the rock will be zero as it is at rest. Let v is the final speed of the ball. It is given by :


v=√(2gh)


v=√(2* 9.8* 13)

v = 15.96 m/s

The kinetic energy of the rock is given by :


E=(1)/(2)mv^2


E=(1)/(2)* 5.2* (15.96)^2

E = 662.27 J

So, the kinetic energy when the rock hits the ground is 662.27 J.

User Morshed
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