If one of the charges is doubled in magnitude while maintaining the same separation between the charges, what is the new magnitude of the force between them?

Question

asked May 28, 2021 216k views

1 Answer

Grufas · Answer 1 · 2021-06-02T09:08:41+0000

Step-by-step explanation:

Force between two charges is given by

F=k(q_1q_2)/(r^2)

where q₁ and q₂ are charges and r is the distance between them.

Here one charge is doubled with keeping all others same.

q₁ = 2 q₁

We have

$F_1=k(q_1q_2)/(r^2)\\\\F_2=k(2q_1q_2)/(r^2)\\\\(F_1)/(F_2)=(k(q_1q_2)/(r^2))/(k(2q_1q_2)/(r^2))\\\\(F_1)/(F_2)=(1)/(2)\\\\F_2=2F_1$

Magnitude of force doubles.