Question

If one of the charges is doubled in magnitude while maintaining the same separation between the charges, what is the new magnitude of the force between them?

Answer 1

Magnitude of force doubles.

Step-by-step explanation:

Force between two charges is given by

`F=k(q_1q_2)/(r^2)`

where q₁ and q₂ are charges and r is the distance between them.

Here one charge is doubled with keeping all others same.

q₁ = 2 q₁

We have

`F_1=k(q_1q_2)/(r^2)\\\\F_2=k(2q_1q_2)/(r^2)\\\\(F_1)/(F_2)=(k(q_1q_2)/(r^2))/(k(2q_1q_2)/(r^2))\\\\(F_1)/(F_2)=(1)/(2)\\\\F_2=2F_1`

Magnitude of force doubles.