Question

Use the balanced equation below to determine how many grams of HNO3 can be produced if we have 20.0 grams of NO2.

3NO2 + H2O --> 2HNO3 + NO

Answer 1

We'll have 18.27 grams of HNO3

Step-by-step explanation:

Step 1: Data given

Mass of NO2 = 20.0 grams

Molar mass of NO2 = 46.01 g/mol

Step 2: The balanced equation

3NO2 + H2O → 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = mass NO / molar mass NO

Moles NO2 = 20.0 grams / 46.01 g/mol

Moles NO2 = 0.435 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 0.435 moles NO2 we'll have 2/3 * 0.435 = 0.290 moles HNO3

Step 5: Calculate mass of HNO3

Mass HNO3 = moles HNO3 * molar mass HNO3

Mass HNO3 = 0.290 moles * 63.01 g/mol

Mass HNO3 = 18.27 grams

We'll have 18.27 grams of HNO3

Answer 2

The answer to your question is 18.26 g of HNO₃

Step-by-step explanation:

Data

mass of HNO₃ = ?

mass of NO₂ = 20 g

Balanced equation

3NO₂ + H₂O ⇒ 2HNO₃ + NO

Checked that the equation is balanced

Reactants Elements Products

3 N 3

7 O 7

2 H 2

This equation is balanced

- Calculate the molecular mass of

- HNO₃ = (1 x 1) + (14 x 1) + (16 x 3) =63 g

- NO₂ = (1 x 14) + (16 x 2) = 46 g

- Use proportions to find the answer

3(46) g of NO₂ --------------- 2(63) g of HNO₃

20 g of NO₂ -------------- x

x = (20 x 126) / 138

x = 2520 / 138

x = 18.26 g of HNO₃