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Quick!!! Solve for the missing lengths using trigonometric ratios.

*
110m
42°
Х

Quick!!! Solve for the missing lengths using trigonometric ratios. * 110m 42° Х-example-1
User Jed Veatch
by
3.7k points

1 Answer

8 votes

Answer:

see explanation

Explanation:

using the tangent ratio in the right triangle to find x

tan42° =
(opposite)/(adjacent) =
(10)/(x) ( multiply both sides by x )

x × tan42° = 10 ( divide both sides by tan42° )

x =
(10)/(tan42) ≈ 11.1 ( to 1 dec. place )

-------------------------------------------------

using the sine ratio to find the hypotenuse h

sin42° =
(opposite)/(hypotenuse) =
(10)/(h) ( multiply both sides by h )

h × sin42° = 10 ( divide both sides by sin42° )

h =
(10)/(sin42) ≈ 14.9 ( to 1 dec. place )

User Kelsey Abreu
by
3.3k points