Question

A football punter accelerates a 0.59 kg football from rest to a speed of 6.6 m/s in 0.34 s, what constant force does the punter exert on the ball?

Answer 1

F= 11.45N

Step-by-step explanation:

Using the formula; F=ma

Where,
`a=(v-u)/(t)`

`F =m*(v-u)/(t)`

m=0.59kg, v=6.6m/s, t=034s u=0 (the body starts from rest

We will input these values into equation 1 to get the force magnitude.

`F =0.59*(6.6-0)/(0.34)`

F= 11.45N