Question

12.) Write y = 1/6 x + 7 in standard form using integers.

a.) –x + 6y = 42

b.) –x + 6y = 7

c.) 6x – y = 42

d.) –x – 6y = 42

Answer 1

Option A

-x + 6y = 42 is the standard form

Solution:

Given that we have to write
`y = (1)/(6)x+7` in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

`y = (1)/(6)x+7`

Let us convert the above equation into standard form

`y = (x)/(6) + 7`

`y = (x)/(6) + (7)/(1)`

Make the denominator same in R.H.S

`y = (x)/(6) + (7 * 6)/(1 * 7)`

Solve the above equation

`y = (x)/(6) + (42)/(6)`

`y = (x+42)/(6)`

Move 6 from R.H.S to L.H.S

`6y = x + 42`

Bring all the terms to one side, leaving only constant on R.H.S

`-x + 6y = 42`

The above equation is of form Ax + By = C

Thus option A is correct