Question

The first stage of the giant Saturn V rocket reached a speed of 2405 m/s at 168 s after liftoff. a. What was the average acceleration in m/s/s? (Enter the magnitude.) b. The acceleration of a falling object if air resistance is negligible is 9.8 m/s/s, called "one g." What was the average acceleration in g's? (Enter the magnitude.)

Answer 1

The theory concerning the kinematic movement tells us that acceleration can be expressed as the change of speed in a finished time, that is, mathematically it can be described as,

`a = (\Delta v)/(t)`

Here,

`\Delta v`= Change in velocity (Initial and final)

t = time

If the body starts from rest, its initial velocity will be zero and its final velocity will be that given in the statement, therefore:

`a = (2405-0)/(168)`

`a = 14.315m/s^2`

Now realizing the conversion of units to 'g' we have to

`a = (14.315m/s^2 )(1g)/(9.8m/s^2)`

`a = 1.46g`