Answer:
There are 6.022 *10^23 atoms in 34.02 grams hydrogen peroxide
Step-by-step explanation:
Step 1: Data given
Hydrogen peroxide = H2O2
Mass of H2O2 = 34.02 grams
Molar mass of H2O2 = 34.01 g/mol
Number of Avogadro = 6.022 *10^23 / mol (This means we have 6.022 *10^23 particles per 1 mol)
Step 2: Calculate moles H2O2
Moles H2O2 = mass H2O2 / molar mass H2O2
Moles H2O2 = 34.02 grams / 34.01 g/mol
Moles H2O2 = 1.000 moles
Step 3: Calculate atoms in H2O2
Number of atoms = number of moles * number of Avogadro
Number of atoms = 1.000 moles * 6.022 *10^23 / mol
Number of atoms = 6.022 *10^23 atoms
There are 6.022 *10^23 atoms in 34.02 grams hydrogen peroxide