Question

A 200 kg stationary cannon fires a 12 kg cannonball to the right at 300 m/s. Please explain.a) Calculate the momentum of the cannon before the collision.b) Calculate momentum of the cannonball before the collision.c) Calculate the total Kinetic Energy before the collision.d) Calculate the momentum of the cannon after the collision.

Answer 1

a) Since before collision the velocity of the cannon is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

b) Since before collision the velocity of the cannonball is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

c)
`\therefore KE=0`

d)
`p=3600\ kg.m.s^(-1)`

Step-by-step explanation:

Given:

mass of the cannon,
`M=200\ kg`

mass of cannonball fired,
`m=12\ kg`

velocity of cannonball,
`v=300\ m.s^(-1)`

a)

Momentum of the cannon before collision:

Since before collision the velocity of the cannon is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

b)

Since before collision the velocity of the cannonball is zero and we know that momentum is the product of mass and velocity so its momentum is also zero.

c)

The velocity before collision is zero.

kinetic energy is given as:

`KE=(1)/(2) m.v^2`

`\therefore KE=0`

d)

Momentum of cannon after collision:

`p=M.v'`

considering the collision to be elastic, its momentum will be equally opposite of the cannonball:

`p=m.v=M.v'`

`p=12*300`

`p=3600\ kg.m.s^(-1)`