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one town, 64% of adults have health insurance. What is the probability that 10 adults selected at random from the town all have health insurance?

User Bearzyj
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1 Answer

3 votes

Answer:

The probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

Explanation:

Consider the provided information.

One town, 64% of adults have health insurance.

Let p = 64% = 0.64

Therefore, q=1-0.64=0.36

We need to find the probability that 10 adults selected at random from the town all have health insurance

Use the formula:
P(x)=^nC_r(p)^r(q)^(n-r)

Here, the value of r is 10.

Substitute the respective values in the above formula.


P(x)=^(10)C_(10)(0.64)^(10)(0.36)^(10-10)


P(x)=(0.64)^(10)(0.36)^(0)\\P(x)=(0.64)^(10)\\P(x)\approx0.01153

Hence, the probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

User Priyashree Bhadra
by
7.9k points

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