Question

one town, 64% of adults have health insurance. What is the probability that 10 adults selected at random from the town all have health insurance?

Answer 1

The probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

Explanation:

Consider the provided information.

One town, 64% of adults have health insurance.

Let p = 64% = 0.64

Therefore, q=1-0.64=0.36

We need to find the probability that 10 adults selected at random from the town all have health insurance

Use the formula:
`P(x)=^nC_r(p)^r(q)^(n-r)`

Here, the value of r is 10.

Substitute the respective values in the above formula.

`P(x)=^(10)C_(10)(0.64)^(10)(0.36)^(10-10)`

`P(x)=(0.64)^(10)(0.36)^(0)\\P(x)=(0.64)^(10)\\P(x)\approx0.01153`

Hence, the probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.