Answer:
Explanation:
The cartesian coordinates is (-2, 2)
So, x = -2 and y = 2
So, r Cos θ = x and r Sin θ = y
r Cos θ = - 2 .... (1)
r Sin θ = 2 .... (2)
Squarring equation (1) and (2) and add
![r^(2){Sin^(2)\theta +Cos^(2)\theta }= (-2)^(2)+2^(2)](https://img.qammunity.org/2021/formulas/mathematics/college/al0adfjwk0jahojoyobpoc1igrd4jlq7t0.png)
![r^(2)=8](https://img.qammunity.org/2021/formulas/mathematics/college/mbinqtw6bdaxcos7nt6gmqlgdw123jcy4y.png)
r = 2.83
Divide equation (2) by equation (1), we get
![tan\theta = - 1](https://img.qammunity.org/2021/formulas/mathematics/college/7tl7dcmqbpxxqnmxls8kd2ulb6z43uevu0.png)
θ = 3π/4
So, the polar coordinates are (2.83 Cos 3π/4, 2.83 Sin 3π/4)