Question

Suppose that tank holds 1% liquid water by volume and 99% vapor water by volume at a temperature of 185oC. What is the quality?

Answer 1

quantity = 0.645749

Step-by-step explanation:

given data

holds liquid water = 1%

hold vapor water = 99%

temperature = 185°C

solution

we know that at temperature 185°C

Specific Volume of Saturated Liquid water (vf) = 0.0011343 m³/kg

and Specific Volume of Saturated Vapor (vg) = 0.17390 m³/kg

so quality will be

quality =
`(vapour*specific\ volume\ water)/(water*specific\ volume\ vapour)` ................1

put here value we get

quality =
`(99*0.0011343)/(1*0.17390)`

quantity = 0.645749