Question

Which of the following is the final concentration of KCl if 500 ml of 0.25 M KCl is diluted to a final volume of 5 L?

0.025 L
0.0025 L
25 L
2.5 L

Answer 1

0.025 M

Step-by-step explanation:

Given data:

Initial volume = 500 mL (0.5 L)

Initial molarity = 0.25 M

Final volume = 5L

Final molarity = ?

Solution:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume

M₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula.

M₁V₁ = M₂V₂

0.25 M × 0.5 L = M₂ × 5 L

0.125 M. L= M₂ × 5 L

M₂ = 0.125 M. L / 5L

M₂ = 0.025 M