Question

HEY‼️‼️ CAN SOMEONE HELP WITH THIS⁉️ 1 and 4 are completed I need 2 3 5 6 7 8 9 USE THE FORMULA SA= ph + 2b B= base p= perimeter

Answer 1

Part 1)
`SA=58\ cm^2`

Part 2)
`SA=90\ ft^2`

Part 3)
`SA=168\ m^2`

Part 4)
`SA=96\ in^2`

Part 5)
`SA=660\ in^2`

Part 6)
`SA=96\ cm^2`

Part 7) Your friend is not correct,
`SA=150\ cm^2`

Part 8)
`SA=486\ in^3`

Part 9)
`SA=94\ ft^2`

Explanation:

we know that

The surface area of a rectangular prism is equal to

`SA=2B+Ph`

where

B is the area of the base of the prism

P is the perimeter of the base of the prism

h is the height of the prism

Part 1) Find the surface area of the rectangular prism

Find the area of the base B

`B=(4)(1)=4\ cm^2`

Find the perimeter of the base

`P=2(4+1)=10\ cm`

we have

`h=5\ cm`

substitute the values in the formula of surface area

`SA=2(4)+10(5)=58\ cm^2`

Part 2) Find the surface area of the rectangular prism

Find the area of the base B

`B=(2)(5)=10\ ft^2`

Find the perimeter of the base

`P=2(2+5)=14\ ft`

we have

`h=5\ ft`

substitute the values in the formula of surface area

`SA=2(10)+14(5)=90\ ft^2`

Part 3) Find the surface area of the rectangular prism

Find the area of the base B

`B=(9)(6)=54\ m^2`

Find the perimeter of the base

`P=2(9+6)=30\ m`

we have

`h=2\ m`

substitute the values in the formula of surface area

`SA=2(54)+30(2)=168\ m^2`

Part 4) Find the surface area of the triangular prism

Find the area of the triangular base B

`B=(1/2)(8)(3)=12\ in^2` ---> the area of triangle

Find the perimeter of the triangular base

`P=8+5+5=18\ in`

we have

`h=4\ in`

substitute the values in the formula of surface area

`SA=2(12)+18(4)=96\ in^2`

Part 5) Find the surface area of the triangular prism

Find the area of the triangular base B

`B=(1/2)(12)(5)=30\ in^2` ---> the area of triangle

Find the perimeter of the triangular base

`P=12+5+13=30\ in`

we have

`h=20\ in`

substitute the values in the formula of surface area

`SA=2(30)+30(20)=660\ in^2`

Part 6) Find the surface area of the triangular prism

Find the area of the triangular base B

`B=(1/2)(6)(8)=24\ cm^2` ---> the area of triangle

Find the perimeter of the triangular base

`P=8+6+10=24\ cm`

we have

`h=2\ cm`

substitute the values in the formula of surface area

`SA=2(24)+24(2)=96\ cm^2`

Part 7) we know that

The surface area of a cube is equal to the area of its six square faces

`SA=6b^2`

where

b is the length side of the cube

we have

`b=5\ cm`

substitute

`SA=6(5^2)`

`SA=150\ cm^2`

therefore

Your friend is not correct

The surface area of the cube is
`SA=150\ cm^2`

Part 8) we know that

The surface area of a cube is equal to the area of its six square faces

`SA=6b^2`

where

b is the length side of the cube

we have

`b=9\ in`

substitute

`SA=6(9^2)`

`SA=486\ in^3`

Part 9) Find the surface area of the rectangular prism (shipping crate)

Find the area of the base B

`B=(5)(4)=20\ ft^2`

Find the perimeter of the base

`P=2(5+4)=18\ ft`

we have

`h=3\ ft`

substitute the values in the formula of surface area

`SA=2(20)+18(3)=94\ ft^2`